(05-27-2021, 12:46 PM)Hogmelon Wrote: If one assumes that all remaining games in the Mavs/Clippers series will be decided by a coin flip, using either a "fair" coin or a coin that has been precisely "weighted" in the Clippers' favor by a specific amount, then the following probabilities would apply:
P(g) = probability that Clippers win the game
P(S) = probability that Clippers win the series
P(g) P(S)
0.5 18.75%
0.55 25.62%
0.6 33.70%
0.65 42.84%
0.68619 50.00%
0.7 52.82%
0.71534 56.00%
0.75 63.28%
0.8 73.73%
Obviously, this series will be decided on the basketball court rather than by coin flips [and P(g) is surely not constant from game to game], but this exercise should at least prove how much a fish needs a bicycle.
OK, guys ...
I was just kidding about the coin flips. These are the real probabilities that really apply to the real-world situation involving the Dallas Mavericks and the Los Angeles Clippers.
[See above FFS!!!]
https://media.giphy.com/media/3o7btS8fHH.../giphy.gif